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find the final equilibirum temperature when 10.0 g of milk at 10.0degC is added to 1.60*10^2 g of coffee with a temperatrure of 90.0degC. Assume the specific heats of coffee and milk are the same as for water (Cp,w=4.19J/g*degC) and disregard the heat capacity of the container


massmilk*cmilk*(Tf-10)+masscoffee(ccoffee)(Tf-90)=0
please show me in simple steps how to solve for Tf

thanks a lot

  • physics -

    massmilk*cmilk*(Tf-10)+masscoffee(ccoffee)(Tf-90)=0

    divide through by specific heat, it goes away.

    10*(Tf-10)+160(Tf-90)=0
    Tf(10+160)-100-160*90=0
    Tf= (14400/170)

  • physics -

    so Tf is 84.70?

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