calculus
posted by bob .
Compute the area of the region in the fi…rst quadrant bounded
on the left by the curve y = sqrt(x), on the right by the curve y = 6  x,
and below by the curve y = 1.

well, looking at the curves, The area will be (x2x1) dy or (6y  y^2 )dy ...check that.. with the limits from y=1 to ymax, or
ymax occurs when
x are the same, or
y^2=6y
y^2+y6=0
(y+3)(y2)=0
so the first quadrant ymax is 2
check that.
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