# Calculus

posted by .

Find:
1)x^2-y^2=15, normal at (-8,7)

• Calculus -

first, find the slope, then the negative reciprocal of that slope.

2x dx-2ydy=0

Put in x,y and find dy/dx.

Now, the normal will be y=mx+b, m is the negative reciprocal of the dy/dx above, solve for b, and you have it.

## Similar Questions

1. ### HS Calculus

Definition of the derivative to calculate f'(x) if f(x) = square root 2x. Find the equation of the tangent & normal line to the graph of f at x=2. Tangent line - y=2x-x Normal line - y = 1/2x +3 I do not know whether these are the …
2. ### statistics

without the use of the standard normal tables, should techniques of calculus be used to find the probabilities concerning a normal distribution?
3. ### Calculus

Find the slope of the normal line to y= ln(15-x) at x=4
4. ### Calculus

Find the slope of the normal line to y= ln(15-x) at x=4
5. ### Calculus (Normal Line, please check my work)

The slope of the line normal to the graph of 4 sin x + 9 cos y = 9 at the point (pi, 0) is: Derivative: 4cosx - 9siny(dy/dx) = 0 (dy/dx) = (-4cosx) / (-9siny) (dy/dx) = (4) / 0 Normal line = -1 / (4/0) Does this mean that the slope …
6. ### Calculus

Write the equation 4x + 5y – 3 = 0 in normal form. Then, find the length of the normal and the angle it makes with the positive x–axis.