Calculus
posted by Jane .
Find:
1)x^2y^2=15, normal at (8,7)

first, find the slope, then the negative reciprocal of that slope.
2x dx2ydy=0
Put in x,y and find dy/dx.
Now, the normal will be y=mx+b, m is the negative reciprocal of the dy/dx above, solve for b, and you have it.