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1)x^2-y^2=15, normal at (-8,7)

  • Calculus -

    first, find the slope, then the negative reciprocal of that slope.

    2x dx-2ydy=0

    Put in x,y and find dy/dx.

    Now, the normal will be y=mx+b, m is the negative reciprocal of the dy/dx above, solve for b, and you have it.

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