math
posted by Anonymous .
I'm a little confused on how to solve this system of equations.
5a=5
6b3c=15
2a+7c=5
Thanks

The first equation gives a = 1 when you divide both sides by 5
Now do the third equation substituting 1 for a
2*1 + 7 c = 5
7 c = 7
c = 1
so now we have a = 1 and c = 1
Use those in the middle equation
6 b  3 (1) = 15
6 b + 3 = 15
6 b = 12
b = 2 
Ah, I get it now. Thanks
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