math
posted by sherry .
Find the limit of the function:
(tanp)(x1)/(tanq)(x1)
as x approaches 1. We're hinted at using the result that sinx/x = 1 as x approaches 0.
Im not sure how we go abt doing this qs.
thanks in advance

as written the answer is simply tanp/tanq
what is tanp?
what is tanq ?
what is p and what is q ?
Does this mean tan (px  p) / tan (qx  q)? or something? 
tanp and tanq is short for tangent p and tangent q respectively(we havent been told where p is a variable or constant; same goes for q)
no it doesnt mean tan (px  p)
it wud be xtanp tanp if u were to multiply it through ..same for denominator
and the answer given is p/q 
(xtanptanP)/(xtanqtanq) as x approachtes zero.
Unless p,q are somehow related to x, it is not equal to p/q. 
to get p/q, it looks like somebody canceled the "tan"
reminded me of the time when one of my students gave this solution to
Lim (sinx)/x as x = 0
= sin
I told him to sin no more, but he didn't get it.
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