Calculus
posted by Andrew .
Using the Disk Method or washer method (im not sure which one)
Find The volume of y=x^3 , y=1 , x = 2
revolving around the X axis

Calculus 
bobpursley
V=PI*INT y^2 dx
=PI INT x^6 dx from x=1 to x=2
PI*y^2 is the area of the disk
dx is its thickness. 
Calculus 
Reiny
I will assume you want to rotate the region bounded by your three curves.
vol = π(integral) (x^6  1)dx
= π[(x^7)/7  x]from 1 to 2
= pi[128/72  (1/7  1)]
= π[127/7  1) cubic units
check my arithmetic, I have been making some silly typing errors lately. 
Calculus 
Damon
Maybe you mean the area between the horizontal line y = 1 and the curve y = x^3 from their intersection at (1,1) to the vertical line x = 2 spun around the x axis?
That would be washers.
inner radius = 1
outer radius = x^3
area of washer = pi (x^3)^2  pi
= pi (x^61)
integrate that times dx from x = 1 to x = 2
pi ( x^7/7  x) at x = 2 = pi 128/7 14/7) = pi (114/7)
pi (x^7/7  x) at x = 1 = pi(1/7  1)= pi (6/7)
so
pi (120/7) 
Calculus 
Damon
Well, we check this time :)

Calculus 
Reiny
noticed that too, lol
but, after all, I am on third cup of coffee.
Respond to this Question
Similar Questions

calculus
find the volume of the solid formed by revolving the region bounded by the graphs of y=x^3,y=1, and x=2 about the xaxis using the disk method. 9 express the answer in terms of pie) i got the answer to be 3/5 pie but im not sure if … 
calc
find the volume of the solid generated by revolving around the xaxis: y=e^(x8), y=0, x=0, x=10 So I know you can use the washer method, but the shell method can also be used and it should be better. The issue is I'm not certain how … 
Calculus  Volume by Integration
Find the volume of the solid generated by revolving the region bounded by the given lines and curves about the yaxis: y=(x2)^32, x=0, y=25 (a)solve by either the disk or washer method (b)solve by the shell method (c)state which … 
Calculus  Volume By Integration
Find the volume of the solid generated by revolving the region bounded by the given lines and curves about the yaxis: y=(x2)^32, x=0, y=25 Solve by either the disk or washer method. I calculated the volume using the shell method … 
Urgent Math
Suppose the area under y = x^2+1 between x = 0 and x = 1 is rotated around the xaxis. Find the volume by using Disk method and shell method. 
Calculus
I would like to know if my answers are correct: Disclaimer: We are allowed to keep our answers in formula form 1. Use the washer method to find the volume of the solid that is generated by rotating the plane region bounded by y=x^2 … 
Calculus
The region enclosed by the graph e^(x/2), y=1, and x=ln(3) is revolved around the xaxis. Find the volume of the solid generated. I don't understand if we have to use the washer method or the disk method for this one because when I … 
Calculus
The region enclosed by the graph e^(x/2), y=1, and x=ln(3) is revolved around the xaxis. Find the volume of the solid generated. I don't understand if we have to use the washer method or the disk method for this one because when I … 
Calculus II: Finding the volume of a revolution
Question: Find the volume of revolution bounded by yaxis, y=cos(x), and y=sin(x) about the horizontal axis. Since the rotation is happening at the horizontal axis, I thought the limits of integration would be [1,1] and if the curves … 
Math  Calculus
Find the volume of the solid given by rotating the region bounded by the curves y=x^2, x=1, x=2, and y=0 around the yaxis a) Use the shell method b) Use the washer method. Be careful with the radius of the washer at different y.