College Algebra

posted by Marlon

I am having a difficult time with this question. Any help whatsoever will be really helpful as I have been pulling an all nighter for my test at 4pm.
The question reads as follows:

Suppose that y=[2-log(100-x)]/0.29 can be used to calculate the number of years y for x percent of a population of 928 web-footed sparrows to die. Approximate the percentage (to the nearest whole percent) of web-footed sparrows that died after 5 years.

The answer is supposed to be 96% but I am just not getting it. I have a feeling its not hard but I'm missing something crucial.

Thanks for all the help!

  1. bobpursley

    .29*5=2-log(100-x)
    log(100-x)=.55
    100-x=3.55
    x=96.4

  2. Marlon

    =/
    I still do not understand. This is my setup.

    5=[2-log(100-x)]/.29
    1.45 = 2-log(100-x)
    -.55 = -log(100-x)
    .55= log(100-x)
    Now I am frozen there... If i take the log of both sides I do have 100-x on the right but obtain -.2596 for the left. The problem would equal 100.2596 and not 96.4.

    In your setup, I am confused as to where the 100-x=3.55 came from.

    Thank you so much, you don't understand how helpful you guys are for taking the time to help us.

  3. bobpursley

    1.45=2-log(100-x)
    -.55=-log(100-x)
    .55=log(100-x)
    take the antilog of each side
    3.458133892=100-x

    You are taking the LOG of both sides. You want the antilog.

  4. Marlon

    Thank you so much!!! I got it!

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