College Algebra
posted by Marlon .
I am having a difficult time with this question. Any help whatsoever will be really helpful as I have been pulling an all nighter for my test at 4pm.
The question reads as follows:
Suppose that y=[2log(100x)]/0.29 can be used to calculate the number of years y for x percent of a population of 928 webfooted sparrows to die. Approximate the percentage (to the nearest whole percent) of webfooted sparrows that died after 5 years.
The answer is supposed to be 96% but I am just not getting it. I have a feeling its not hard but I'm missing something crucial.
Thanks for all the help!

College Algebra 
bobpursley
.29*5=2log(100x)
log(100x)=.55
100x=3.55
x=96.4 
College Algebra 
Marlon
=/
I still do not understand. This is my setup.
5=[2log(100x)]/.29
1.45 = 2log(100x)
.55 = log(100x)
.55= log(100x)
Now I am frozen there... If i take the log of both sides I do have 100x on the right but obtain .2596 for the left. The problem would equal 100.2596 and not 96.4.
In your setup, I am confused as to where the 100x=3.55 came from.
Thank you so much, you don't understand how helpful you guys are for taking the time to help us. 
College Algebra 
bobpursley
1.45=2log(100x)
.55=log(100x)
.55=log(100x)
take the antilog of each side
3.458133892=100x
You are taking the LOG of both sides. You want the antilog. 
College Algebra 
Marlon
Thank you so much!!! I got it!
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