8x^0(10x^-2)(-2x^-6y^7)= ???
please help
First of all, 8x^0 = 8
So rewrite it as
(8*2)(5/x^2 - y^7/x^6)
= (16/x^2)(5 - y^7/x^4)
There are other ways to write it.
please help
So rewrite it as
(8*2)(5/x^2 - y^7/x^6)
= (16/x^2)(5 - y^7/x^4)
There are other ways to write it.