posted by myra ko .
A bodybuilder is holding a 20-kg steel barbell above her head. How much force would she have to exert if the barbell were lifted underwater?
You will need to look up the density of steel.
The weight of the barbell under water will be
20 kg * g - V *(densityH2O)* g
V * g [densitysteel) - densityH2O)
The weight in water will be the weight in air (20 g = 196 Newtons) multiplied by [1 - (densityH2O/densitysteel)]