Genetics

posted by .

Phenylketonuria is a metabolic disease of humans that results from an autosomal recessive gene. If the frequency of phenylketonurics in the population is 9/10,000, what is the probability that two normal individuals will produce a diseased child?

  • Genetics -

    (9/10,000)? Is that the frequency of a phenyketonuria child, or the frequency of the recessive gene. The problem statement is uncertain.

    If the 9 tenthousandts is the frequency of phenylketonuria people, then that is the frequency two normal individuals will produce a diseased child.

    If the 9 ten thousandths is the frequence of the recessive gene, then the frequency of children is the square of that.

  • Genetics -

    I think its the frequency of the gene this is a Hardy-Weignberg problem

    Thanks!

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Biology 11 U

    In the U.S. 1 out of 10 000 babies is born with phenylketonuria (PKU). The disease is caused by a recessive allele. The frequency of individuals in the U.S. population born with PKU corresponds to q squared. What is the given information?
  2. Genetics

    Phenylketonuria, a Metabolic disease in humans, is caused by a recessive allele, k. If two heterozygotes marry and plan a family of six children: a)what is the probability that all will be unaffected?
  3. Genetics

    Given below is a pedigree in which the inheritance of an autosomal dominant disease gene is being followed. Linked to the disease gene (3 cM = 3% recombination away) is a RFLP marker with 2 alleles (5 kb and 3 kb). Given the DNA marker …
  4. Genetics

    A certain form of albinism in humans is recessive and autosomal. Assume that 1% of the individuals in a given population are albino. Assuming that the population is in Hardy-Weinberg equilibrium, what percentage of the individuals …
  5. Genetics

    A certain form of albinism in humans is recessive and autosomal. Assume that 1% of the individuals in a given population are albino. Assuming that the population is in Hardy-Weinberg equilibrium, what percentage of the individuals …
  6. Genetics

    β-thalassemia is a human genetic disease that is inherited in an autosomal recessive manner. Individuals with β-thalassemia produce abnormal hemoglobin which results in a reduced ability to carry oxygen in their blood. The …
  7. biology

    Consider the pedigree below. This pedigree represents a family with a rare genetic disease. Note two very important assumptions: Individuals who marry into the family may carry a disease allele. The disease is completelely penetrant. …
  8. Biology

    you are studying a single-gene locus with two alleles in a population that is in Hardy-Weinberg equilibrium. Examination of a large sample of individuals from the population reveals there are six times as many heterozygotes as there …
  9. biology

    In a laboratory population of diploid, sexually reproducing organisms a certain trait is determined by a single autosomal gene and is expressed as two phenotypes. A new population was created by crossing 102 pure–breeding (homozygous) …
  10. Math

    1. Cystic fibrosis (CF), a life-threatening lung disease, is caused from the inheritance of a recessive allele from both parents for the CFTR gene. In order for this disease to manifest itself, one needs to be homozygous recessive …

More Similar Questions