Derivatives
posted by George .
Find dy/dx for the function, xyx12y3=0.
Is the answer 14,I got this from 1112=0, which solves to 14.

ydx+xdydx12dy=0
y + x y' 12 y'=1
y'= (1y)/(x12)
posted by George .
Find dy/dx for the function, xyx12y3=0.
Is the answer 14,I got this from 1112=0, which solves to 14.
ydx+xdydx12dy=0
y + x y' 12 y'=1
y'= (1y)/(x12)