# Chemistry

posted by .

NaC2H3O2 (aq) + HCl (aq) = NaCl (aq) + ?

• Chemistry -

no one has answered this question

• Chemistry -

HC2H3O2.
Just a double decomposition (or double displacement).

## Similar Questions

1. ### chem

Calculate [H3O] in the following solutions. 5.15x10-2M HCl and 7.62x10-2M NaC2H3O2 Responses HCl + NaC2H3O2. It appears there is an excess of H^+ which will react with NaC2H3O2 to form HC2H3O2. That gives you a buffer of C2H3O2 and …
2. ### chemistry

How many grams of NaCl will be produced when 22.85 g of HCl are neutralized by an excess of NaOH according to the equation below?
3. ### chemistry

theoretical yield of NaCl using 0.016 mols HCl with HCl + NaOH - NaCl + H2O as the equation for the reaction
4. ### Chemistry

To prepare a 400 mL solution of .7500 M NaC2H3O2, how many grams of NaC2H3O2 would be needed?
5. ### Chemistry

Naoh (aq) + HCl (aq) --> NaCl (aq) + H2O (l) Using the dT determined in part 1, calculate the heat capacity of the calorimeter. Enthalpy of reaction= -58.3 kj/mol, Cs (NaCl = 3.91j/g C)density of 1 M NaCl = 1.037g/mL. dT= 12.88 …
6. ### General Chemistry

What volume of 1.0 M HCl would react completely with 0.20 grams of NaC2H3O2*3H2O?
7. ### Chemistry

I need help I can't seem to get the right answer. Please help! 1/2 H_2 (g) + 1/2 Cl_2 (g) --> HCl (g) -92.3 kJ/mol Na(s) + 1/2 O_2(g) + 1/2H_2(g) --> NaOH(s) -426.8 kJ/mol NaCl(s) --> Na(s) + 1/2Cl_2(g) 411.1 kJ/mol H_2O(l) …
8. ### Chemistry

To a mixture of NaCl and Na2CO3 with a mass of 1.300 g was added 55.00 mL of 0.243 M HCl (an excess of HCl). The mixture was warmed to expel all of the CO2 and then the unreacted HCl was titrated with 0.100 M NaOH. The titration required …
9. ### chemistry- gaz and stoechiometry

We have to prepare 500 gr of a HCl solution 15% by mass: H2SO4 + NaCl at a Temperature of 100°C NAHSO4 is also produced The equation is: H2SO4 + NaCl->NaHSO4 + HCl 1) How many grams of H2SO4 93% by mass and of NaCl do we need if …
10. ### chemistry

1.2 mol HCl and 3.9 mol NaOH react to this equation, HCl + NaOH=NaCl + H20 If the limited reactant id HCl, calculate the amount of NaCl formed in moles. Please help and explain how to solve this so I may understand it better please …

More Similar Questions