Please check my work
3M solution of NaOH (1 liter worth)
molecular weight: 39.99
3 x 39.99= 119.97 grams dilute to 1000mL
3 M solution of HCl (1 L)
c1v1=c2v2
(12M)(?)= (3M)(1000mL)
?= 250 mL
please check thank you
Yes,if you started with 12M of acid. YOu diluted to 1/4, which means you want one part acid, three parts water.
Correct on the sodium hydroxide.
To check your work, let's calculate the amounts of NaOH and HCl needed to make a 3M solution in 1 liter of solution.
For the 3M NaOH solution:
The molecular weight of NaOH is 39.99 g/mol.
To make a 3M solution in 1 liter (1000 mL) of solution, you need to calculate the amount of NaOH needed.
3 M NaOH means 3 moles of NaOH in 1 liter of solution.
So, the number of moles of NaOH required is:
3 moles/L x 1 L = 3 moles
To convert moles of NaOH to grams, we use the molecular weight:
3 moles x 39.99 g/mol = 119.97 grams
Therefore, you are correct that you would need to measure out 119.97 grams of NaOH and dilute it to 1000 mL (1 liter) with solvent (usually water) to prepare a 3M NaOH solution.
For the 3M HCl solution:
Using the equation c1v1=c2v2 (where c represents concentration and v represents volume), we can solve for the volume of a more concentrated HCl solution needed to make a 3M solution in 1 liter of solution.
12 M x ? mL = 3 M x 1000 mL
? mL = (3 M x 1000 mL) / 12 M
? mL = 250 mL
Therefore, your calculation for the 3M HCl solution is correct, and you would need to measure out 250 mL of a 12M HCl solution and dilute it to 1000 mL (1 liter) with solvent to prepare a 3M HCl solution.
Overall, your calculations and solutions are correct for both the 3M NaOH and 3M HCl solutions. Well done!