Math problem check
posted by Shawn .
Subtract and Simplify:
4a^2/(ab)(4b^28ab)/(ba)
I have the answer as 4(a+b)^2/(ab)
or should it be 4(ab)^2/(ab)

just the numerator..
4a^28ab + 4b^2, right?
4(ab)^2
Now does that reduce with the denominator? 
Okay I have the answer as 4(ab) is that right

What about
4a^2/(ab)(4b^28ab)/(ba)
I thought that you would multiple the second part of the equation by 1
(4b^28ab)/(ba)
to get the common LCD of ab
So I thought the equation would be 4a^2/(ab) + (4b^2 + 8ab)/(ab)
I have the answer as 4(a+b)^2/(ab)
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