PRE CALC

posted by .

The x-intercept of the graph of f(x) = sqrt(x - 1) - 2 is (5, 0)

  • PRE CALC -

    What is the question?

  • PRE CALC -

    IS THIS CORRECT... IS THE X INTERCEPT (5,0)?

  • PRE CALC -

    Yes.

  • PRE CALC -

    THANK U

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. MATH

    I need to simply this equation, but I got stuck. h/(4-sqrt(16+h)) = y First, I multiplied (4+sqrt(16+h)/(4+sqrt(16+h) to both sides, and I ended up with h(4+sqrt(16+h)/-h. Is this correct?
  2. Pre-Calc

    I'm stuck on a pre-calc problem. I need to find y as a function of x, where the constant c is a positive number for In(y-1)+In(y+1)= -x+c express your question as ln[(y-1)(y+1)] = -x+c change that to exponential form e^(-x+c) = (y-1)(y+1) …
  3. math-Inverse functions

    f(x)=-4x-2 & g(x)=5x-6. Find (f*g) and state domain. f(x)-x^2-1 what is the equation for f^-1(x)?
  4. Math

    1.Write the equation 5x+y-2=0 in normal form. 5x+y-2=0 5x+y=2 (add two to both sides) Standard form (Ax+By=C)---> 5x+y=2 Y-intercept (when x equals 0) 5x+y-2=0 5x+y=2 5(0) +y=2 y=2 X-intercept (when y equals 0) 5x+y-2=0 5x+y=2 5x+0=2 …
  5. College Algebra

    1.The graph of y = - 1/2 |x - 5| - 3 can be obtained from the graph of y = |x| by which transformations?
  6. Pre-calc

    find a possible polynomial equation of degree 4 if the zeroes are -1,2, and 5, the graph touches the x-axis at -1 but does not cross through, and the y intercept is -5
  7. calc 1

    When graphing the integral of sin(x^2) is there a way to shift the graph vertically, without just tacking "+c" on the end?
  8. Pre-Calc/Trig...

    Stuck on these two questions, help me please. The graph of y=3x^2-4x+2 opens downwards. True or False?
  9. Pre-Calc/Trig...

    Am i correct? The graph of y=3x^2-4x+2 opens downwards. FALSE The graph of y=2x^2-4x+2 has a y-intercept of (0,1). FALSE
  10. Calc

    The graph of f ′(x) is continuous and increasing with an x-intercept at x = 0. Which of the following statements is false?

More Similar Questions