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39 people and their dogs went to a carnival.
between people and dogs, there are 124 legs.
how many people brought their dogs?

  • math -

    Usually, people have 2 legs and dogs have 4.

    39(2) + 4X = 124

    78 + 4X = 124

    4X = 46

    X = 11.5

    If your data are correct, there must have been one two-legged dog or a dog with six legs. (Maybe there might have been two dogs with 5 legs each! Another possibility is that two of the people were amputees!) Check your original numbers.

    I hope this helps. Thanks for asking.

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