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A horse runs off of a 11 meter high cliff into the sea. The horse is running at a speed of 3.6 m/s. How much time does the horse spend in the air? How far from the base of the cliff is the horse when it hits the water?

  • physics -

    Time in the air is given by:
    (1/2) g T^2 = 11 m

    V * T = horizontal distance traveled

  • physics -

    First, how long in the air?

    h=1/2 g t^2 solve for t.

    How far away horizontally?

    d=3.6m/s * time

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