# MATH

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solve

(2s + 5)(s+1)=-1

am I on the right track?

2s^2 +2s=5s=5+-1
2s^2+7s+5=-1
2s^2+7s=-6

where do i go from here?

• MATH -

You need to get zero one one side of the equation, and then try to factor the quadratic term on the other side.

2s^2 + 7s +6 = 0
(2s+3)(s+2) = 0
Both 2s + 3 and s+2 are sero, so
s = -3/2 or -2

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