posted by .

The period of revolution of a planet around the sun is the time it takes for the planet to complete one orbit of the sun. The period, P years, is give by Kepler's third law P^2=D^3, where D is the average distance from the sun in astronomical units (AU). One AU is the average distance f the Earth fromt he sun. Use the average distance formt he sun to find the period of revolution for Jupiter; 5.20 AU to the nearest tenth of a year.

I don't get that, the teacher said the answer was 11.9 I think. Anyone care to explain how?


  • Math -


    5.20 AU is the distance so:

    P^2=D^3 is equivalent to:
    5.20^3 is 140.608, 140.608 is the period.
    So the new equation would be:
    Since you now know that 140.608 is the period squared, the opposite of squaring is square rooting. So this is how you would write it.
    It asked for the nearest tenth of the year so rounding up would make the answer 11.9
    So the period of revolution for Jupiter is 11.9 years.


Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Astrophysics

    I'm having trouble understanding the formulas for determining a planet's distance and mass. A planet's distance is related to the period of revolution and the mass of the central star (e.g, the sun). The relationship is called Kepler's …
  2. Physics

    A 21.0-kg satellite has a circular orbit with a period of 2.37 h and a radius of 8.50×106 m around a planet of unknown mass. If the magnitude of the gravitational acceleration on the surface of the planet is 7.10 m/s2, what is the …
  3. Math

    The average radius r in meters of a planet's path around the sun is given by the formula r=[(3.35 x 10^18)t^2]^1/3, where t is the time in seconds that it takes the planet to go around the sun. a. Rewrite the equation using the root …
  4. college algebra

    Kepler’s third law. According to Kepler’s third law of planetary motion, the ratio t^2/r^3 has the same value for every planet in our solar system. R is the average radius of the orbit of the planet measured in astronomical units …
  5. earth

    planet is in circular orbit around the Sun. Its distance from the Sun is 2.9 times the average distance of Earth from the Sun. What is the period of this planet, in Earth years?
  6. Physics

    A planet with mass 7 x 1024 kg orbits a sun with a period of 1 Earth's years. The speed of the planet around that sun is constant and |v|=43000 m/s. What is the mass of that sun?
  7. Math

    the time x (in days), that it takes a planet to revolve around the sun can be approximated by the equation x=0.407√(d^3),where d is the mean distance of the planet from the sun in millions of miles. It takes Venus approximately …
  8. physics

    According to Kepler's third law, the orbital period T of a planet is related to the radius R of its orbit by T2 R3. A planet's orbit is larger than Earth's by a factor if 3.39. What is the planet's orbital period?
  9. Science

    istance of a planet from sun is four times the distance of the planet frpm earth.How many years will the planet take to complete one revolution of sun?
  10. Physics?

    What information do you need to calculate the altitude of a satellite’s planet-synchronous orbit?

More Similar Questions