Algebra
posted by Nicole .
Solve for y in terms of x . Determine if y is a function of x . If it is, rewrite using notation and determine the domain.
xsquared+12x3y+9=0
is it
xsquared + 12x +9=3y
f(x)=xsquared + 12x + 6=y ?

no, should be
y = (1/3)x^2 + 4x + 3
(each term had to be divided by 3)
and yes, it is a function whose domain is the set of real numbers 
y=x^2+12x+6
Now, is y a function of x?
What is the domain of x? 
please disregard

Y=5+6
y=7+6X=2
7+=6=4
y=86=8+4=12
SO THE APPLICATION OF X IS ABOUT TO MOVE EXACTLY WERE IT IS AND NEGATIVELY MOVE TO THE POSITIVE NUMBER SO THE ANSWER IS
NEGATIVE 12
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