chem

posted by .

A solution is made by mixing 20.0 mL of toluene C6H5CH3d=0867gmL with 150.0 mL of benzene C6H6d=0874gmL. Assuming that the volumes add upon mixing, the molarity (M) and molality (m) of the toluene are

____M and

_____m.

  • chem -

    molarity=molestolulent/volume solution

    volume solution=.150+.020
    Moles toulene=20*.0867g/ml*molmass

    molarity=molestoluene/kg solvent

    kgsolvent=150*.0874 kg

    I am wondering what was the problem on this?

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. chemistry

    A solution is made by mixing 20.0 mL of toluene C6H5CH3d=0.867gmL with 150.0 mL of benzene C6H6d=0.874gmL. Assuming that the volumes add upon mixing, what are the molarity (M) and molality (m) of the toluene
  2. Chemistry

    A solution is made by mixing 20.0 mL of toluene C6H5CH3d=0867gmL with 140.0 mL of benzene C6H6d=0874gmL. Assuming that the volumes add upon mixing, the molarity (M) and molality (m) of the toluene are?
  3. ap chem

    i am stuck on this problem from school A solution is made by mixing 30.0 mL of toluene C6H5CH3d=0.867gmL with 130.0 mL of benzene C6H6d=0.874gmL . Assuming that the volumes add upon mixing, the molarity (M) and molality (m) of the …
  4. Chemistry

    A solution is made by mixing 20.0 mL of toluene C6H5CH3d=0867gmL with 140.0 mL of benzene C6H6d=0874gmL. Assuming that the volumes add upon mixing, the molarity (M) and molality (m) of the toluene are... ______ M and ______ m. I need …
  5. Chemistry

    A solution is made by mixing 35.0 mL of toluene C6H5CH3d=0867gmL with 125.0 mL of benzene C6H6d=0874gmL. Assuming that the volumes add upon mixing, the molarity (M) and molality (m) of the toluene are
  6. chemistry

    A solution is made by mixing 35.0 mL of toluene C6H5CH3d=0867gmL with 125.0 mL of benzene C6H6d=0874gmL. Assuming that the volumes add upon mixing, the molarity (M) and molality (m) of the toluene are how do you find the L of SOLUTION
  7. chemistry

    A solution is made by mixing 35.0 mL of toluene C6H5CH3d=0867gmL with 125.0 mL of benzene C6H6d=0874gmL. Assuming that the volumes add upon mixing, the molarity (M) and molality (m) of the toluene are so the L of solution is...?
  8. chemistry

    A solution is made by mixing 25.0 mL of toluene C6H5CH3d=0867gmL with 135.0 mL of benzene C6H6d=0874gmL. Assuming that the volumes add upon mixing, the molarity (M) and molality (m) of the toluene are ?
  9. chemistry

    can someone please help me with this? i've been stuck on this one forever... A solution is made by mixing 25.0 mL of toluene C6H5CH3d=0867gmL with 135.0 mL of benzene C6H6d=0874gmL. Assuming that the volumes add upon mixing, the molarity
  10. chemistry

    can someone help me with this please? i've been stuck on this one forever... A solution is made by mixing 25.0 mL of toluene C6H5CH3d=0867gmL with 135.0 mL of benzene C6H6d=0874gmL. Assuming that the volumes add upon mixing, the molarity

More Similar Questions