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i am stuck on this problem from school

A solution is made by mixing 30.0 mL of toluene C6H5CH3d=0.867gmL with 130.0 mL of benzene C6H6d=0.874gmL . Assuming that the volumes add upon mixing, the molarity (M) and molality (m) of the toluene are

  • ap chem -

    How many grams of toluene do you have? How many moles is that?

    What is the mass of the benzene?

    Molarity=molesToulene/volumesolutioninLiters

    molality=molesToulene/kgOfSolvent

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