URGENT SUMMER SCHOOL CALCULUS

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A force of magnitude 15 N is the resultant of two forces, one of which has a magnitude of 8 N and acts at an angle of 30° to the resultant. Find the magnitude and direction of the other force...how do I begin to solve this!?

• URGENT SUMMER SCHOOL CALCULUS -

Law of cosines:

The side you are looking for is opposite the 30 degree angle.

c^2=15^2+8^2-2*15*8cos30
I get a magnitude of about 9
For the angle, Iwould use law of sines. Draw a sketch first.

• URGENT SUMMER SCHOOL CALCULUS -

Well, I am taking the resultant to be along the x axis and the 8 N vector at 30 degrees above the x axis.
Then our vector of length x will lie below the x axis an angle y
Now there are two things that have to be true
8 cos 30 + x cos y = 15
8 sin 30 - x sin y = 0
or
6.93 + x cos y = 15
4 - x sin y = 0
or
x cos y = 8.07
x sin y = 4
but we know sin y / cos y = tan y so divide
tan y 4/8.07
y = 26.4 degrees below x axis
which is
26.4 + 30 = 56.4 degrees from original vector
x = 4/sin26.4 = 9 Newtons

• URGENT SUMMER SCHOOL CALCULUS -

You can also solve this problem purely algebraically without using geometry or drawing diagrams. If we denote the resultant force by R, the force of magnitude 8 N at an angle of 30° to the resultant by y and the unknown force by x, we have:

x + y = R ------->

x = R - y

Square both sides:

x^2 = R^2 + y^2 - 2 R dot y

The inner product R dot y can be expressed as:

R dot y = |R||y| cos(30°)

This then gives |x| = about 9 N

To find the angle of x to the resultant (let's call this theta), you can take the inner product of x with R and use that

x dot R = |x| |R| cos(theta)

We have:

x = R - y

taking the inner product of both sides with R gives:

x dot R = R^2 - y dot R =

R^2 -|y||R|cos(30°)

If we divide both sides by |x||R| we get cos(theta) on the l.h.s.:

cos(theta) = [|R| - |y|cos(30°)]/|x|

this gives theta = 26.4°

• URGENT SUMMER SCHOOL CALCULUS -

My diagram doesn't work out, I have done it to scale, but I can't figure out how to draw it. I got the same answers as everyone above, I used the cosine and sine law to do mine (I got my answer after I posted :) ). But my diagram looks weird. Any thoughts?

• URGENT SUMMER SCHOOL CALCULUS -

15 cos

• URGENT SUMMER SCHOOL CALCULUS -

two forces of magnitude 10N and 30N act upon a body in direction making angle of 30 and 45 with x axis find the ressultant force?

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