Algebra

posted by .

I was wondering if I had number 2 correct; the only way to know the answer was to provide the entire answer for number 1. Thanks in advance.

1. Suppose that a market research company finds that at a price of p = \$20, they would sell x = 42 tiles each month. If they lower the price to p = \$10, then more people would purchase the tile, and they can expect to sell x = 52 tiles in a month’s time. Find the equation of the line for the demand equation. Write your answer in the form p = mx + b. (Hint: Write an equation using two points in the form (x,p).

P=-x+62

A company’s revenue is the amount of money that comes in from sales, before business costs are subtracted. For a single product, you can find the revenue by multiplying the quantity of the product sold, x, by the demand equation, p.

b. Substitute the result you found from part a into the equation R = xp to find the revenue equation. Provide your answer in simplified form.

R = -x^2 + 62 x

The portion of the company’s fixed costs allotted to this product is \$300, and the supplier’s cost for a set of tile is \$6 each. Let x represent the number of tile sets. The costs of doing business for a company can be found by adding fixed costs, such as rent, insurance, and wages, and variable costs, which are the costs to purchase the product you are selling.

c. If b represents a fixed cost, what value would represent b?

b = 300 (fixed costs)

d. Find the cost equation for the tile. Write your answer in the form C = mx + b.

m = 6 (variable costs)
x = number of tile sets

C = 6x + 300

The profit made from the sale of tiles is found by subtracting the costs from the revenue.
e.Find the Profit Equation by substituting your equations for R and C in the equation . Simplify the equation.

Profit = Revenue - Costs
Profit = -x² + 62x - (6x + 300)
Profit = -x² + 62x - 6x - 300
Profit = -x² + 56x - 300

f.What is the profit made from selling 20 tile sets per month?
Profit = -x² + 56x - 300
Profit = -(20)² + 56(20) - 300
Profit = -400 + 1120 - 300
Profit = 420

g.What is the profit made from selling 25 tile sets each month?
Profit = -x² + 56x - 300
Profit = -(25)² + 56(25) - 300
Profit = -625 + 1400 - 300
Profit = 475

Profit = -x² + 56x - 300
Profit = -(0)² + 56(0) - 300
Profit = -0 + 0 - 300
Profit = -300
The company will spend \$300 for fixed costs regardless of sales, so without any sales, they lose \$300 from their account each month.

i.Use trial and error to find the quantity of tile sets per month that yields the highest profit.
For a quadratic equation with a negative leading coefficient, there is always a maximum value at the vertex, which is located on the equation's Axis of Symmetry. The Axis of Symmetry is found from x = -b/(2*a), so here you get:

Profit = -x² + 56x - 300
x = -56/(2*-1) = 28
28 tile sets would generate the maximum profit.

j.How much profit would you earn from the number you found in part i?
Profit = -x² + 56x - 300
Profit = -(28)² + 56(28) - 300
Profit = -784 + 1568 - 300
Profit = 484

k.What price would you sell the tile sets at to realize this profit (hint, use the demand equation from part a)?
P=-x+62
P= -28 + 62
Price = 34

2.The break even values for a profit model are the values for which you earn \$0 in profit. Use the equation you created in question one to solve P = 0, and find your break even values.
-x² + 56x - 300 = 0
-(x² - 56x + 300) = 0
-(x - 50)(x - 6) = 0
x = 50 or x = 6
The company will break even if they sell 50 sets or 3 sets of tiles.

• Algebra -

It looks correct to me, including the part #2 that you asked about. You also explained the problem and your work very clearly. I appreciate that. Nice job

• Algebra -

yeahoooo ty ty ty =)

Similar Questions

1. Algebra

1.In this problem, we will analyze the profit found for sales of decorative tiles. A demand equation (sometimes called a demand curve) shows how much money people would pay for a product depending on how much of that product is available …
2. ALGEBRA

I HAVE TO SOLVE THE FOLLOWING PROBLEMS FOR AN ALGEBRA ASSIGNMENT DUE SUNDAY. I HAVE FIGURED OUT MOST OF THE ANSWERS BUT AM STUCK ON A FEW. IF ANYONE CAN TELL ME IF MY EXISTING ANSWERS ARE CORRECT AND POINT ME IN THE RIGHT DIRECTION/GIVE …
3. Algebra

1. In this problem, we will analyze the profit found for sales of a certain product. A demand equation (sometimes called a demand curve) shows how much money people would pay for a product depending on how much of that product is available …
4. Algebra

. In this problem, we will analyze the profit found for sales of a certain product. A demand equation (sometimes called a demand curve) shows how much money people would pay for a product depending on how much of that product is available …
5. Algebra

Library Research Assignment Please help with Discussion board problem Suppose that the number of new homes built, H, in a city over a period of time, t, is graphed on a rectangular coordinate system where time is on the horizontal …
6. Algebra II

Suppose a market research company finds that at a price of p = \$20, they would sell x=42 tiles each month. If they lower the price to p = \$10, them more people would purchase the tile, and they can expect to sell x = 52 tiles in a …
7. algbra 1b

can someone tell me if i have the answer correct a. Suppose a market research company finds that at a price of p = \$40, they would sell x = 27 tiles each month. If they lower the price to p = \$15, then more people would purchase the …
8. algebra

Suppose a market research company finds that at a price of p=\$25,they would sell x=56 tiles each month. If they lower the price to p=\$20, then more people would purchase the tile, and they can expect to sell x=66 tiles in a month's …
9. algebra

Two part question: Suppose a market research company finds that at a price of p=\$25, they would sell x=56 tiles each month. If they lower the price to p=\$20, then more people would purchase the tile, and they can expect to sell x=66 …
10. math

A market research company finds that traffic in a local mall over the course of a day could be estimated by the function P(t)=-1800cos((pie(9))/6 t)+1800 where P,is the number of people going to the mall ,and t is the time, in hours …

More Similar Questions