Algebra
posted by Ashli .
I was wondering if I had number 2 correct; the only way to know the answer was to provide the entire answer for number 1. Thanks in advance.
1. Suppose that a market research company finds that at a price of p = $20, they would sell x = 42 tiles each month. If they lower the price to p = $10, then more people would purchase the tile, and they can expect to sell x = 52 tiles in a month’s time. Find the equation of the line for the demand equation. Write your answer in the form p = mx + b. (Hint: Write an equation using two points in the form (x,p).
P=x+62
A company’s revenue is the amount of money that comes in from sales, before business costs are subtracted. For a single product, you can find the revenue by multiplying the quantity of the product sold, x, by the demand equation, p.
b. Substitute the result you found from part a into the equation R = xp to find the revenue equation. Provide your answer in simplified form.
R = x^2 + 62 x
The portion of the company’s fixed costs allotted to this product is $300, and the supplier’s cost for a set of tile is $6 each. Let x represent the number of tile sets. The costs of doing business for a company can be found by adding fixed costs, such as rent, insurance, and wages, and variable costs, which are the costs to purchase the product you are selling.
c. If b represents a fixed cost, what value would represent b?
b = 300 (fixed costs)
d. Find the cost equation for the tile. Write your answer in the form C = mx + b.
m = 6 (variable costs)
x = number of tile sets
C = 6x + 300
The profit made from the sale of tiles is found by subtracting the costs from the revenue.
e.Find the Profit Equation by substituting your equations for R and C in the equation . Simplify the equation.
Profit = Revenue  Costs
Profit = x² + 62x  (6x + 300)
Profit = x² + 62x  6x  300
Profit = x² + 56x  300
f.What is the profit made from selling 20 tile sets per month?
Profit = x² + 56x  300
Profit = (20)² + 56(20)  300
Profit = 400 + 1120  300
Profit = 420
g.What is the profit made from selling 25 tile sets each month?
Profit = x² + 56x  300
Profit = (25)² + 56(25)  300
Profit = 625 + 1400  300
Profit = 475
h.What is the profit made from selling no tile sets each month? Interpret your answer.
Profit = x² + 56x  300
Profit = (0)² + 56(0)  300
Profit = 0 + 0  300
Profit = 300
The company will spend $300 for fixed costs regardless of sales, so without any sales, they lose $300 from their account each month.
i.Use trial and error to find the quantity of tile sets per month that yields the highest profit.
For a quadratic equation with a negative leading coefficient, there is always a maximum value at the vertex, which is located on the equation's Axis of Symmetry. The Axis of Symmetry is found from x = b/(2*a), so here you get:
Profit = x² + 56x  300
x = 56/(2*1) = 28
28 tile sets would generate the maximum profit.
j.How much profit would you earn from the number you found in part i?
Profit = x² + 56x  300
Profit = (28)² + 56(28)  300
Profit = 784 + 1568  300
Profit = 484
k.What price would you sell the tile sets at to realize this profit (hint, use the demand equation from part a)?
P=x+62
P= 28 + 62
Price = 34
2.The break even values for a profit model are the values for which you earn $0 in profit. Use the equation you created in question one to solve P = 0, and find your break even values.
x² + 56x  300 = 0
(x²  56x + 300) = 0
(x  50)(x  6) = 0
x = 50 or x = 6
The company will break even if they sell 50 sets or 3 sets of tiles.
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