calculus

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f(x)=(9x^2–8)^6(4x^2–5)^11

Find f'(x)

I got

(9x^2-8)^6 *11(4x^2-3)^10*8x+((4x^2-3)^11)6(9x^2-8)^5(18x)

but im doing something wrong can someone check my work please

  • calculus -

    I don't see an error. How do you know it is wrong?

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