calculus
posted by John .
f(x)=(9x^2–8)^6(4x^2–5)^11
Find f'(x)
I got
(9x^28)^6 *11(4x^23)^10*8x+((4x^23)^11)6(9x^28)^5(18x)
but im doing something wrong can someone check my work please

I don't see an error. How do you know it is wrong?