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Which equation has the complex number 4-3i as a root?
(1) x^2+6x-25=0
(2) x^2-6x+25=0
(3) x^2+8x-25=0
(4) x^2-8x+25=0


I have no clue how to do it!!!PLEASE HELP!!!Please guide by step by step!!THANKS A LOT~!!!!

  • math-repost -

    Look at the serds. To get a serd that is negative, you have to have a or c negative. That means only 1 or 3 can be correct. Now, which yields sqrt (b^2-4ac) to be 6i ?

  • math-repost -

    I still don't get it

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