Inverses
posted by Dennis .
Problem:
cos[arccos(sqrt3/2)arcsin(1/2)]
This is what I have:
cos [(5pi/6)(11pi/6)]
cos (6pi/6) or pi
giving an answer of 1
What I am wondering is should I use the (11pi/6) or should I use (pi/6) because of the restrictions on arcsin x (pi/2)<=x<=(pi/2)
Thank you in advance.

I would use the smaller angle. It should not matter on the final answer.

Thank you very much.
The answer doesn't change, but my trig teacher wants to see all of work, and I just wasn't sure which figure to use.
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