# chemistry

posted by .

A bottle of HCL is 14.0M and has a density of 1.08 grams/mL. What is the molality of the HCL?

• chemistry -

14.0 M means 14.0 mols in 1000 mL of solution. If the solution has a density of 1.08 g/mL, then 1000 g will have a mass of 1080 grams. Then molality = mols/kg solvent. Post your work if you get stuck.

## Similar Questions

1. ### Chemistry :(

Calculate the molality, % percent composition by weight, and the mole fraction of HCl in an aqueous 12M HCl solution that has a density of 1.20 g?
2. ### Chemistry

Calculate the molality of HCl in an aqueous 12M HCl solution that has a density of 1.20g/mL
3. ### chemistry

I have a 0.25 m aquaeous solution of HCL. It's density is 1.05 g/ml. WHat is the % by mass (m/m) of this solution?
4. ### chemistry urg!

Hydrochloric acid is sold as a concentrated acqueous solution. If the molarity of HCl is 12.0 and its density is 1.18 g/ml. calculate A) MOLALITY B)THE % BY MASS OF HCl in the solution
5. ### Chemistry

How do I prepare 100mL of 10g/L HCl from concentrated HCl(37%HCl, density 1.19g/mL) Is it 2.28mL of conc HCl dilute to 100mL with water?
6. ### Chemistry

1) Prepare 100mL of 10%w/w HCl from 37%concentrated HCl(density of 37%HCl =1.19g/ml) 2) Prepare 100mL of 10%w/v HCl from 37% concentrated HCl(density of 37%HCl=1.19g/ml) Can you please show the calculation steps for 1) & 2)?
7. ### chemistry

suppose u r given a conc soln of hcl which is known to be 37% hcl & has a soln density of 1.19g/ml. What is the molarity and molality of hcl in this soln
8. ### chemistry

bottle of hcl which is 40 mass%and has density of 1.20g /ml. calculate ml to be taken from this bottle to prepare 500 ml solution of 0.2 M
9. ### chemistry

How do I prepare 100mL of 10g/L HCl from concentrated HCl(37%HCl, density 1.19g/mL) Is it 2.28mL of conc HCl dilute to 100mL with water?
10. ### Chemistry

Perpare 500ml of 1M HCl solution from a bottle of concentrated 37%(W/W) HCL stock with a density of 1.19g/ml. 37%= 37/100 x 100 therefore mass is 37g molarity = mol/vol 1= mol/0.5 mol=0.5 mass of Hcl needed = molxmr mass = 0.5 x 36.5 …

More Similar Questions

Post a New Question