posted by Jon .
Four resistors of 10.0 each are connected in parallel. A combination of four resistors of 10.0 each is connected in series along with the parallel arrangement. What is the equivalent resistance of the circuit?
This is all I understand. Can you explain step by step and show how to get the answer?
1/R = 1/Ra + 1/Rb + 1/Rc +1/Rd
? = 1/10.0 + 1/10.0 + 1/10.0 + 1/10.0
1/Req= 4/10 or Req=2.5 ohms.
Now, add the 40 ohms in series, so Rtotal=42.5ohms