I don't know how to factor this polynomial.
r^3+6r^2+11r+6
Please help.
First see if any root that is an integer factor of 6 works in solving
r^3 + 6r^2 + 11r +6 = 0
Try these prime factors of 6:
+ or - 1,2,3, or 6.
+ roots won't work because all polynomial terms would be positive.
-1 works; therefore r+1 is a factor.
Divide (r+1) into r^3+6r^2+11r+6 for the other factor, using polynomial long division. You should get r^2 + 5r + 6.
That can also be factored. Do that and you're done.