posted by Kendra .
A 437.7 N child and a 237.1 N child sit on either end of a 2.5 meter long seesaw.
How far from the 437.7 N child should the pivot be placed to ensure rotational equilibrium? disregard the mass of the seesaw. answer in units of m.
I will be happy to critique your thinking.
The sum of the moments about the piviot has to be zero.
Let the heavier child be x meters from the fulcrum. The lighter child will be 2.5 - x meters from the fulcrum.
437.7 x = 237.1 (2.5 -x)
Solve for x.
674.8 x = 592.75
x = 0.88 m