Algebra
posted by G .
I am trying to solve the sytems of equations using the elimination method.
2x+4y=10
3x+3y=6
I tied multiplying the first equation by 2 and the second by 4. Then I tried multiplying the first equation by 3 and the secondy by 3.
The book says the answers are 3,1.
I am not getting these answers.

Try to multiply first equation by 3 and second equation by 2. You will end up with 6x and 6x, you can eliminate those and then use the substitution method to find y.

Multiply the second equation by 2/3
2x+4y=10
2x+2y=4
add the equations
6y=6
y=1
Put that y back into either equation, and solve for x.