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Two charges are arranged on the x axis so that there is a positive charge of 3.6 micro C at the orgin and a negative charge of .2.5 micro C located 2.5 centimeters to its right. to the nearest cetimeter, where on the x axis should a positive charge be placed so that the net force on it is zero?

  • Physics -

    Let the charge be to the right of the negative charge, and see if one can get a solution

    F1 + F2=0
    k3.6*q/x^2 - k2.5q/(x-2.5)^2=0
    solve for x.

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