I need to know if I need to further reduce my answer or if I leave it the way I have it. I have the original problem and then my answer.
-b +or- sqrt b^2=4ac/2a
answer x= -1/2 +or- 1/10
I do not know what your problem is. That is sort of the quadratic equation:
x = [-b +/- sqrt(b^2-4ac)]/2a
and you would get the two answers but I did not see the original quadratic so do not know if right or not (although I can do it backwards).
now to do it backwards
if x = -.5 and x = -.1 are solutions then
(x+.5)(x+.1) = 0
x^2 + .6 x + .05 = 0
100 x^2 + 60 x + 5 = 0
oh,divide by 5
20 x^2 + 12 x + 1 = 0
To determine whether you need to further reduce your answer or leave it as it is, let's simplify the given answer and compare it to the original problem.
The original problem is a quadratic equation in the form ax^2 + bx + c = 0, where a, b, and c are constants. According to the quadratic formula, the solution to this equation is given by:
x = (-b ± √(b^2 - 4ac)) / (2a)
Now let's compare this with the expression you have provided:
x = -1/2 ± 1/10
To compare both expressions, we need to find a common denominator for the fractional terms. The common denominator is 10; hence, we can rewrite the expression as:
x = (-5/10 ± 1/10) = (-5 ± 1) / 10
Now, we can further simplify the expression:
x = (-5 + 1) / 10 = -4 / 10 = -2/5
or
x = (-5 - 1) / 10 = -6 / 10 = -3/5
Therefore, the simplified form of the answer is x = -2/5 or x = -3/5.
In conclusion, you need to further reduce your answer to x = -2/5 or x = -3/5, from x = -1/2 ± 1/10.