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posted by Jon Tuesday, March 4, 2008 at 12:10pm.

Find the sum of a geometric series for which a1=1,r=2,and n=6. Sn=a1(1-r^n)/1-r S6=1(1-2^6)/1-2 S6=1(1-64)/1-2 S6=63/1 63 (answer)

right

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