How would you solve 3x times x squared = 4
Well
3x * x^2 = 3x^3
So now you have 3x^3 = 4
then x^3 = 4/3
so x = the cubed root of (4/3)^(1/3)
Where ^ indicates "to the power of".
Whoops, the answer should just be
x = (4/3)^(1/3) or x = the cube root of (4/3)
Bad grammar :P
What is the lateral area, total area, and volume of a rectangular solid whose l=7, w=6, & h=2?
To solve the equation 3x * x^2 = 4, we can start by simplifying the equation.
First, we multiply 3x with x^2. This gives us 3x * x^2 = 3x^3. So now the equation becomes 3x^3 = 4.
To solve for x, we need to isolate it on one side of the equation. We can do this by dividing both sides of the equation by 3:
(3x^3) / 3 = 4 / 3
Simplifying further, we get:
x^3 = 4/3
To solve for x, we need to take the cube root of both sides of the equation:
∛(x^3) = ∛(4/3)
This simplifies to:
x = ∛(4/3)
So the solution to the equation 3x * x^2 = 4 is x = ∛(4/3).