math

posted by Cynthia

how would you solve [(*square root*125)^4]^1/6

1. Dan

The "square root" of a number simply means the number is raised to the power of 1/2 or 0.5.

So your question becomes (((125)^1/2)^4)^1/6

When you have exponents beside each other you simply multiply them.

So the question becomes 125^(0.5*4*1/6)

= 125^(1/3)

Now what number multiplied by itself 3 times gives you 125?

2. Cynthia

5^3 = 125, but now what do i do?

3. Dan

5^3 = 125

So how do we get 125^(1/3) from this?

Simply take the cubed root of both sides.

(5^3)^(1/3) = 125(^1/3)

What then, must the cubed root of 125 be?

4. Cynthia

five. got it now thanks so much

5. Dan

No problem :)

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