math
posted by Cynthia .
how would you solve [(*square root*125)^4]^1/6

The "square root" of a number simply means the number is raised to the power of 1/2 or 0.5.
So your question becomes (((125)^1/2)^4)^1/6
When you have exponents beside each other you simply multiply them.
So the question becomes 125^(0.5*4*1/6)
= 125^(1/3)
Now what number multiplied by itself 3 times gives you 125? 
5^3 = 125, but now what do i do?

5^3 = 125
So how do we get 125^(1/3) from this?
Simply take the cubed root of both sides.
(5^3)^(1/3) = 125(^1/3)
What then, must the cubed root of 125 be? 
five. got it now thanks so much

No problem :)
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