# Math

posted by .

Find the exact solution to 6x^2+1=-8x by using the Quadratic Formula.

A)-4+-(sqrt10)
B)-4+-(sqrt22)/6
C)-2+-2(sqrt10)/3
D)-4+-(sqrt10)/6
I chose C

x=-b+-(sqrtb^2-4ac)/2a
x=--8+-(sqrt-8^2-4(6)(1))/2(6)
x=8+-(sqrt64-24)/12
x=8+-(sqrt40)/12
x= C

• Math -

correct

• Math -

In the first one a = 6, b = 8 and c = 1
x = [-8 +-sqrt (64-24)]/12
=[-8 +-sqrt(4*10)]/12
=[-8 +-2sqrt(10)]/12
=[-4 +-sqrt10]/6

• Math -

Thanks for picking up on that
As George would have said,
"I guess I mislooked"

• Math(im confused) -

Please explain x = [-8 +-sqrt (64-24)]/12
=[-8 +-sqrt(4*10)]/12

• Math -

64 - 24 = 40 = 4*10

• Math(so how is my answer wrong? -

i don't understand

• Math -

Which don't you understand:
64-24 = 40, or
40 = 4 x 10?
Or my use of * for x when multiplying?
We do that often here to avoid confusion with the algebraic variable x.

• Math(please explain b/c I don't think im wrong) -

I did all the steps

• Math -

a = 6
b = 8
c = 1
why did you use -8 for b?
why dis you not divide -b by 2a?
you left a bracket out, wrecking everything
x = [ -8 +/- sqrt (64 - 4*6*1) ] /2*6
x = [ -8 +/- sqrt(64-24) ] / 12
x = [ -8 +/- sqrt (4*10) ] /12
x = [ -8 +/- 2 sqrt (10) ] / 12
x = [ -4 +/- sqrt(10) ] / 6
I agree with drwls :)

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