can you factor this 4x squared + 80x -276=0
Yes, that's the right equation. Good job!
Yes, you can factor it. Start by taking out a common 4.
i cant get the right factor
right now i got 4(x 23) (x 2) because i factored 4 out am i doing this right i need help
Certainly! To factor the quadratic equation 4x^2 + 80x - 276 = 0, we need to find two binomials that, when multiplied together, give us the original equation.
Step 1: Divide all the terms by the common factor, if there is one. In this case, the equation does not have a common factor other than 1, so we can skip this step.
Step 2: Multiply the coefficient of the quadratic term (4) by the constant term (-276). The result is -1104.
Step 3: Find two numbers that multiply to give -1104 and add up to the coefficient of the linear term (80). In this case, the numbers are 46 and 24 because 46 * 24 = -1104, and 46 + 24 = 70.
Step 4: Rewrite the quadratic equation by splitting the linear term (80x) into two terms, using the two numbers found in step 3. So we have: 4x^2 + 46x + 24x - 276 = 0.
Step 5: Group the terms and factor by grouping. Factor out the greatest common factor from the first two terms and from the last two terms. In this case, take out 2x from the first two terms and 12 from the last two terms: 2x(2x + 23) + 12(2x + 23) = 0.
Step 6: Notice that we now have a common binomial factor, (2x + 23), which can be factored out: (2x + 23)(2x + 12) = 0.
Therefore, the factored form of the quadratic equation 4x^2 + 80x - 276 = 0 is (2x + 23)(2x + 12) = 0.