posted by Jen .
A copper calorimeter can with mass .100 kg contains .160 kg of water and .018 kg of ice in thermal equilibrium at atmospheric pressure. If .750 kg of lead at a temperature of 255 degrees Celsius is dropped into the can what is the final temperature of the system if no heat is lost to the surroundings?
The sum of all the heats gained is zero (some of the heats gained will be negative, as in heat lost).
Heatgainedwater+ heatgainedlead+ heatgained calorimeter+ heat gained ice=0
mw*cw*(Tf-0) + ml*cl*(Tf-255) + mc*cc*(tf-0) + massice*latentheatfusionice =0
Solve for Tf