Algebra II
posted by Lucy .
One number is two less than a second number. If you take onehalf of the first number and increase in by the second number, the result is at least 41. Find the least possible value for the second number.
HELP PLEASE!!!! I hate word problems!!!

1st#=x2
2nd#=x
1/2(x2)+x=41
x2+2x=82
3x=84
x=28
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