chem
posted by Alexa .
hey I am really stumped...I would really appreciate some help with this question
1.0560g of antacid is weighed and mixed with 75.00mL of excess 0.1126 M HCL. The excess acid required 4.68mL of 0.1008 M NaOH or back titration Calculate the neutalizing power of the antacid in terms of mmol H+ per gram of antacid

Solve the excess acid first.
MolesExcessAcid= moles NaOH
VolumeExcess*MolariatyEx= .00468L*.1008
solve for volume excess, then subtract it from the original volume, and you can then solve to antacid titration.