Business Math II
posted by Dan
Photography - Two men and a woman are lined up to have their picture taken. If they are arranged at random, what is the probability that
(A) the woman will be on the left in the picture?
(B) the woman will be in the middle in the picture?
1 woman, three possible positions.
the Pr of the woman in any position is 1/3
so I don't have to do any Permutations right? just a simple Pr(E)=n(E)/n(S)
If you want to do it that way, go ahead:
you will get the same answer: one thing, three possible positions.
i don't know