What is the velocity of an object dropped from a height of 350 m when it hits the ground?
Vf=Vi + g t
I will be happy to critique your thinking. What has this to do with calculus?
To find the velocity of an object dropped from a height, we can use the equation for freefall:
v = √(2gh)
where v is the velocity, g is the acceleration due to gravity, and h is the height.
In this case, the height (h) is 350 m and the acceleration due to gravity (g) is approximately 9.8 m/s².
Plugging in the values, we get:
v = √(2 * 9.8 * 350)
Calculating this:
v = √(6860) ≈ 82.8 m/s
Therefore, the velocity of the object when it hits the ground is approximately 82.8 m/s.
To determine the velocity of an object dropped from a height of 350 m when it hits the ground, we can use the equation:
v = √(2gh)
Where:
v is the velocity
g is the acceleration due to gravity (approximately 9.8 m/s²)
h is the height
1. Plug in the given values into the equation:
v = √(2 * 9.8 m/s² * 350 m)
2. Multiply the values inside the parentheses:
v = √(6860 m²/s²)
3. Take the square root of 6860 m²/s²:
v ≈ 82.79 m/s
Therefore, the velocity of the object when it hits the ground is approximately 82.79 m/s.