algebra

posted by .

thank everyone that site helped but now i just have to practice. for now can someone tell me how does 3x=7-4x x=1
which one do you minus or subtract from the equation?

3x = 7 - 4x

The first thing you need to do is get the unknowns on one side of the equation. You also need to change the sign of the part you move.

3x + 4x = 7
7x = 7
x = 1

I answered my own question is this right? 3x=7-4x 3x+4x=7-4x+4x
7x=7 7divided by 7 is one

Right! :-)

Similar Questions

1. math

can anyone help me with these 3 problems I am trying to check my daughters hoime work it has bee na few years. 1. The sum of n and twenty -two, multiplied by three, is 78 2. the product of z and 17 is less than or equal to the difference …
2. Calc, Implicit Differentiation

1) Let x^3 + y^3 = 28. Find y"(x) at the point (3, 1). y"(3)= The correct answer is: -2*3*28 = -168 3x^2 + 3y^2(dx/dy) = 0 6x + 6y(dx/dy) = 0 dx/dy = -6(3)/6(1) = -3 That's as far as i get... i don't even know if that's started right... …

4. algebra

Please can someone help me with these? factoring 2x^2+5x-3 and 3x^2-15x+12 Thanks in advance!!! well rose. you nedd to distrubte the first one or find the gcf but there anit one, the second one do the same thing. for further questions
5. Algebra

Solve the quadratic equation. 4x^2-8x+3=5 4x² - 8x +3 - 5 = 0 4x²- 8x - 2 = 0 2x²- 4x -1 = 0 this is as far as I got. I am stuck and do not know what to do next can some one please help?
6. Maths

solve the following pair of simultaneous equation: (x/a)+(y/b)=1 (x/b)+(y/a)=1 can someone help please?
7. sra McGuin

Just wanted to thank you for all of your help - - will need help again but right now just getting ready for conversation test - which I just have to practice and practice
8. Algebra

I am re posting this for fear that it was overlooked earlier. I have also decided to show my work in the hopes of preventing any issues that might arise. Solve the absolute value equation. I y+3 I +5=2y Would the solutions be 8=y and …
9. Physics

Hello everyone, I have made measurements of the periods of a pendulum attached to a stationary point at a certain height h. When plotting the periods as a function of the square root of the length minus the height it gives us a straight …
10. Thank you Jiskha and Reiny

I just wanted to write a post to thank everyone who helps out. I haven't found people to be very grateful on this site so I thought i'd take a moment to tell you how awesome you guys are. Special thanks to Reiny for all the helpful …

More Similar Questions