Algebra
posted by Jess .
Solve the quadratic equation.
4x^28x+3=5
4x²  8x +3  5 = 0
4x² 8x  2 = 0
2x² 4x 1 = 0
this is as far as I got. I am stuck and do not know what to do next can some one please help?
divide by two:
x² 2x 1/2 = 0
Now add 1.5 to each side to complete the square:
x² 2x 1/2 +1.5 = +1.5
(x1)^{2}=1.5
subtract 1.5 from each side
(x1)^{2} 1.5 = 0
Now you have a difference of squares (1.5 is sqrt (3/2) squared..)
[x1sqrt3/2][x1+sqrt3/2] = 0
divide by two:
x² 2x 1/2 = 0
Now add 1.5 to each side to complete the square:
x² 2x 1/2 +1.5 = +1.5
(x1)^{2}=1.5
subtract 1.5 from each side
(x1)^{2} 1.5 = 0
Now you have a difference of squares (1.5 is sqrt (3/2) squared..)
[x1sqrt3/2][x1+sqrt3/2] = 0
the answer is 0
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