Math
posted by Sissy .
The sum of two numbers is 112. The second is 7 more than 4 times the first. What are the two numbers?
Am I doing something wrong? I seem to be stuck.
x + y =112
(x+7)4y=112
The second equation should be:
y+7=4x
Should be the 2nd equation.
The 2nd one:
y
is 7 more. This is a little tricky. "Is" means an equals sign, but you're also saying that number to left left is 7 more than what's on the right. So you still have to add 7 to the left to balance it out.
y+7=
"four times the first" is:
4x
y+7 = 4x
Can you solve it from there?
Matt
Made a mistake. In my paragraph that reads "is 7 more" I should say SUBTRACT 7 from the left side:
y7=
That will leave you with the equation:
y7=4x
My apologies.
Matt
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