# Math

posted by
**Sissy**
.

The sum of two numbers is 112. The second is 7 more than 4 times the first. What are the two numbers?

Am I doing something wrong? I seem to be stuck.

x + y =112

(x+7)4y=112

The second equation should be:

y+7=4x

Should be the 2nd equation.

The 2nd one:

y

is 7 more. This is a little tricky. "Is" means an equals sign, but you're also saying that number to left left is 7 more than what's on the right. So you still have to add 7 to the left to balance it out.

y+7=

"four times the first" is:

4x

y+7 = 4x

Can you solve it from there?

Matt

Made a mistake. In my paragraph that reads "is 7 more" I should say SUBTRACT 7 from the left side:

y-7=

That will leave you with the equation:

y-7=4x

My apologies.

Matt