# Chemistry II

posted by Jayd

A 12.00 mL sample of sulfuric acid from an automobile battery requires 34.62 mL of 2.42 M sodium hydroxide solution for complete neutralization. What is the molarity of the sulfuric acid?

H2SO4 + 2NaOH ==> Na2SO4 + 2H2O
molarity NaOH x liters NaOH = mols NaOH.
mols H2SO4 = 1/2 mols NaOH
molarity H2SO4 x L H2SO4 = mols H2SO4

solve for molarity H2SO4.

(2.42 mol NaOH / 1000 mL0 (34.62 mL) (1 mol H2SO4 / 2 mol NaOH) / (12.00 mL / 1000mL) = 3.49 M

right.

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