ALGEBRA 1
posted by DANIELLE .
Please check for me.Without drawing the graph of the given equation determine
(a)how many xintercepts the parabola has
(b)whether it vertex lies above, below or on the axis.
1. y=x^25x+6
I use the determinant
sqrt b^2 4ac
(5)^24(1)(6))=1
There are two real numbers
The parabola has two X intercepets
The parabola opens downward and its vertex lies above the axis.
2.Y=X^2+2X1
(2)^24(1)(1)=0
There is one real number
one xintercept
The parabola opens upward and its vertex lies on the axis.
Thanks Much!!!
well done
Thanks Reiny
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