math,correction
posted by jasmine20 .
is this correct:
solve by using the quadratic formula
5x^2+x=3
what i keep getting is this:
(1 +/ sqrt 61)/(10) or should i reduce the denominator to 5 or is my whole answer incorrect?
(1 +/ sqrt 61)/(10) looks correct. You do not need to reduce it down, it already is. Nice job, I'm impressed!
(1 +/ sqrt 61)/(10) is the correct answer.
no number divides into 10 and the numbers on top, so you are done
some people would write this as 1/10 +/ sqrt(61)/10 but what would be the advantage of that?
Respond to this Question
Similar Questions

math,correction please..
(x)/(x2)  (x+1)/(x) = (8)/(x^22x) I keep getting x = 6 can someone show me how you guys are getting x = 10 The lowest commond denominator is x(x2) x/x *(x)/(x2)  (x+1)/(x) *(x2)/(x2)=(8)/x(x2) multiplying both sides by the … 
math,help,algebra I
I need help can someone help me get unstuck and let me know if i am correct.thank you. solve by completing the square. 4x^2+2x3=0 this is what i am doing: i used the quadratic equation. so where i am is in this step: x = (2 (+) … 
math,correction
i am really trying is this correct. solve: 5(x2)^2 = 3 MY ANSWER THAT I GOT IS: X = 2 + (SQRT (3) )/(5) no. 5(x2)^2 = 3 (x2)^2 = 3/5 x2 = + sqrt (3/5) x= 2 + sqrt (3/5) so the whole fraction of 3/5 is inside the sqrt yes 
MATH,correction
IS THIS CORRECT NOW. solve by using the quadratic formula. x^2 = 55 My answer: x = (5 + SQRT (5))/(2) I don't see any x term, so b is zero. sorry it suppost to read that first 5x5 
math,correction please
Problem #1 Solve by completing the square 2x^24x11=0 My answer: x = (2+/sqrt 26)/(2) Problem #2 Solve by using the quadratic formula x^24x60=0 My answer: x = (2+/sqrt 16)/(2) You did not do it completeing the square. Please show … 
math,correction
is this correct: solve: 5(x2)^2=3 My answer: (10 +/ sqrt 15)/(5) looks like you expanded, then used the formula and you got the right answer properly reduced. I think you are getting this!!! I don't want to confuse you but I would … 
math,correction
Is this correct now. Problem #1 solve by completing the square. 2x^2+8x+3=0 My answer: x=2 +/ sqrt (5)/(2) Problem #2 solve by using the quadratic formula 5x^2+3x+1=0 My answer: No solution are defined. You are not completing the … 
Calculus  Second Order Differential Equations
Solve the initialvalue problem. y'' + 4y' + 6y = 0 , y(0) = 2 , y'(0) = 4 r^2+4r+6=0, r=(16 +/ Sqrt(4^24(1)(6)))/2(1) r=(16 +/ Sqrt(8)) r=8 +/ Sqrt(2)*i, alpha=8, Beta=Sqrt(2) y(0)=2, e^(8*0)*(c1*cos(0)+c2*sin(0))=c2=2 y'(0)=4, … 
Calculus
Please look at my work below: Solve the initialvalue problem. y'' + 4y' + 6y = 0 , y(0) = 2 , y'(0) = 4 r^2+4r+6=0, r=(16 +/ Sqrt(4^24(1)(6)))/2(1) r=(16 +/ Sqrt(8)) r=8 +/ Sqrt(2)*i, alpha=8, Beta=Sqrt(2) y(0)=2, e^(8*0)*(c1*cos(0)+c2*sin(0))=c2=2 … 
Math
Solve for the zeros of the function using the quadratic formula. 3x^2=4x+6 I know what the quadratic formula is but when I put it into the formula I keep getting an error on the graphing calculator.